23:09 · Nov 21, 2021 · Sun
对于上述代码，请问 `bar` 函数中的局部变量 `f` 在程序退出前是否会被恰当地析构？
Anonymous Quiz
Well-defined behavior，一定会被析构
Well-defined behavior，一定不会被析构
Implementation-defined behavior
Unspecified behavior
Undefined behavior
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